3.1198 \(\int \frac{\sqrt{a+b x+c x^2}}{(b d+2 c d x)^4} \, dx\)

Optimal. Leaf size=39 \[ \frac{2 \left (a+b x+c x^2\right )^{3/2}}{3 d^4 \left (b^2-4 a c\right ) (b+2 c x)^3} \]

[Out]

(2*(a + b*x + c*x^2)^(3/2))/(3*(b^2 - 4*a*c)*d^4*(b + 2*c*x)^3)

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Rubi [A]  time = 0.0140489, antiderivative size = 39, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.038, Rules used = {682} \[ \frac{2 \left (a+b x+c x^2\right )^{3/2}}{3 d^4 \left (b^2-4 a c\right ) (b+2 c x)^3} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[a + b*x + c*x^2]/(b*d + 2*c*d*x)^4,x]

[Out]

(2*(a + b*x + c*x^2)^(3/2))/(3*(b^2 - 4*a*c)*d^4*(b + 2*c*x)^3)

Rule 682

Int[((d_) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[(2*c*(d + e*x)^(m +
1)*(a + b*x + c*x^2)^(p + 1))/(e*(p + 1)*(b^2 - 4*a*c)), x] /; FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b^2 - 4*
a*c, 0] && EqQ[2*c*d - b*e, 0] && EqQ[m + 2*p + 3, 0] && NeQ[p, -1]

Rubi steps

\begin{align*} \int \frac{\sqrt{a+b x+c x^2}}{(b d+2 c d x)^4} \, dx &=\frac{2 \left (a+b x+c x^2\right )^{3/2}}{3 \left (b^2-4 a c\right ) d^4 (b+2 c x)^3}\\ \end{align*}

Mathematica [A]  time = 0.0184316, size = 38, normalized size = 0.97 \[ \frac{2 (a+x (b+c x))^{3/2}}{3 d^4 \left (b^2-4 a c\right ) (b+2 c x)^3} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[a + b*x + c*x^2]/(b*d + 2*c*d*x)^4,x]

[Out]

(2*(a + x*(b + c*x))^(3/2))/(3*(b^2 - 4*a*c)*d^4*(b + 2*c*x)^3)

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Maple [A]  time = 0.042, size = 38, normalized size = 1. \begin{align*} -{\frac{2}{3\, \left ( 2\,cx+b \right ) ^{3}{d}^{4} \left ( 4\,ac-{b}^{2} \right ) } \left ( c{x}^{2}+bx+a \right ) ^{{\frac{3}{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2+b*x+a)^(1/2)/(2*c*d*x+b*d)^4,x)

[Out]

-2/3*(c*x^2+b*x+a)^(3/2)/(2*c*x+b)^3/d^4/(4*a*c-b^2)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x+a)^(1/2)/(2*c*d*x+b*d)^4,x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [B]  time = 5.27809, size = 205, normalized size = 5.26 \begin{align*} \frac{2 \,{\left (c x^{2} + b x + a\right )}^{\frac{3}{2}}}{3 \,{\left (8 \,{\left (b^{2} c^{3} - 4 \, a c^{4}\right )} d^{4} x^{3} + 12 \,{\left (b^{3} c^{2} - 4 \, a b c^{3}\right )} d^{4} x^{2} + 6 \,{\left (b^{4} c - 4 \, a b^{2} c^{2}\right )} d^{4} x +{\left (b^{5} - 4 \, a b^{3} c\right )} d^{4}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x+a)^(1/2)/(2*c*d*x+b*d)^4,x, algorithm="fricas")

[Out]

2/3*(c*x^2 + b*x + a)^(3/2)/(8*(b^2*c^3 - 4*a*c^4)*d^4*x^3 + 12*(b^3*c^2 - 4*a*b*c^3)*d^4*x^2 + 6*(b^4*c - 4*a
*b^2*c^2)*d^4*x + (b^5 - 4*a*b^3*c)*d^4)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\sqrt{a + b x + c x^{2}}}{b^{4} + 8 b^{3} c x + 24 b^{2} c^{2} x^{2} + 32 b c^{3} x^{3} + 16 c^{4} x^{4}}\, dx}{d^{4}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**2+b*x+a)**(1/2)/(2*c*d*x+b*d)**4,x)

[Out]

Integral(sqrt(a + b*x + c*x**2)/(b**4 + 8*b**3*c*x + 24*b**2*c**2*x**2 + 32*b*c**3*x**3 + 16*c**4*x**4), x)/d*
*4

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Giac [B]  time = 1.28705, size = 277, normalized size = 7.1 \begin{align*} \frac{12 \,{\left (\sqrt{c} x - \sqrt{c x^{2} + b x + a}\right )}^{4} c^{\frac{5}{2}} + 24 \,{\left (\sqrt{c} x - \sqrt{c x^{2} + b x + a}\right )}^{3} b c^{2} + 18 \,{\left (\sqrt{c} x - \sqrt{c x^{2} + b x + a}\right )}^{2} b^{2} c^{\frac{3}{2}} + 6 \,{\left (\sqrt{c} x - \sqrt{c x^{2} + b x + a}\right )} b^{3} c + b^{4} \sqrt{c} - 2 \, a b^{2} c^{\frac{3}{2}} + 4 \, a^{2} c^{\frac{5}{2}}}{12 \,{\left (2 \,{\left (\sqrt{c} x - \sqrt{c x^{2} + b x + a}\right )}^{2} c + 2 \,{\left (\sqrt{c} x - \sqrt{c x^{2} + b x + a}\right )} b \sqrt{c} + b^{2} - 2 \, a c\right )}^{3} c^{2} d^{4}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x+a)^(1/2)/(2*c*d*x+b*d)^4,x, algorithm="giac")

[Out]

1/12*(12*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^4*c^(5/2) + 24*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^3*b*c^2 + 18*(
sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*b^2*c^(3/2) + 6*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*b^3*c + b^4*sqrt(c) -
2*a*b^2*c^(3/2) + 4*a^2*c^(5/2))/((2*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*c + 2*(sqrt(c)*x - sqrt(c*x^2 + b*
x + a))*b*sqrt(c) + b^2 - 2*a*c)^3*c^2*d^4)